Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Potential & Equipotentials›Question 4

JEE Main 2026 (22 Jan, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2026 (22 Jan, Shift 2)

Q4JEE Main 2026 · 22 JAN · SHIFT 2Easy

Electric Potential & Equipotentials

Three small identical bubbles of water having same charge on each coalesce to form a bigger bubble. Then the ratio of the potentials on one initial bubble and that on the resultant bigger bubble is:

Show answer and solution

Answer: (a)

  1. Charge is conserved: Q=nqQ = nq; volume is conserved: 43πR3=n⋅43πr3⇒R=n1/3r\frac{4}{3}\pi R^3 = n\cdot\frac{4}{3}\pi r^3 \Rightarrow R = n^{1/3}r
  2. V′=kQR=knqn1/3r=n2/3VV' = \frac{kQ}{R} = \frac{knq}{n^{1/3}r} = n^{2/3}V
  3. VV′=132/3\frac{V}{V'} = \frac{1}{3^{2/3}}
  4. So the answer is (a) 1:32/31 : 3^{2/3}.
Report a mistake

More questions on Electric Potential & Equipotentials