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MHT CET 2021 (23 Sep, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2021 (23 Sep, Shift 1)

Q125MHT CET 2021 · 23 SEP · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Three solid spheres each of mass ' $M$ ' and radius ' $R$ ' are arranged as shown in the figure. The moment of inertia of the system about YY' will be

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Answer: (a)

Top sphere has YY' as a diameter: $\frac{2}{5}MR^2$ .
Bottom two touch YY' ( $d = R$ ): $2\left(\frac{2}{5}+1\right)MR^2 = \frac{14}{5}MR^2$ .
$I = \frac{16}{5}MR^2$ , so the answer is (a).

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