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JEE Main 2009 (AIEEE) · Beats

Beats question from JEE Main 2009 (AIEEE)

Q67JEE Main 2009 · AIEEEEasy

Beats

Three sound waves of equal amplitudes have frequencies (v−1), v, (v+1).(v-1),\ v,\ (v+1). They superpose to give beats. The number of beats produced per second will be:

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Answer: (b)

  1. Adding the three waves: y=Asin⁡(2πvt)[1+2cos⁡(2πt)]y = A\sin(2\pi vt)\left[1 + 2\cos(2\pi t)\right]
  2. Amplitude A(1+2cos⁡2πt)A(1 + 2\cos 2\pi t) repeats every 1 s; in each second ∣1+2cos⁡2πt∣|1 + 2\cos 2\pi t| has two maxima (at cos⁡=1\cos = 1 and cos⁡=−1\cos = -1)
  3. So 2 beats per second: the answer is (b) 22.
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