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MHT CET 2024 (9 May, Shift 2) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2024 (9 May, Shift 2)

Q72MHT CET 2024 · 9 MAY · SHIFT 2Medium

Moment of Inertia & Radius of Gyration

Three thin rods, each mass ' 2 M ' and length ' L ' are placed along $x, y$ and z axis which are mutually perpendicular. One end of each rod is at origin. Moment of inertia of the system about x - axis is

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Answer: (a)

Rod along x: $I = 0$ .
Rods along y and z (mass $2M$ ), end on the axis: $\frac{2ML^2}{3}$ each.
$I = \frac{4ML^2}{3}$ , so the answer is (a).

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