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MHT CET 2024 (15 May, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2024 (15 May, Shift 1)

Q71MHT CET 2024 · 15 MAY · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Three thin rods, each of mass ' MM ' and length ' LL ' are placed along X,YX, Y and Z axes which are mutually perpendicular. One end of each rod is at origin. M. I. of the system about Z axis is

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Answer: (c)

  1. Rod along Z lies on the axis: I=0I = 0.
  2. Rods along X and Y are perpendicular to Z with one end on it: ML23\frac{ML^2}{3} each.
  3. I=2ML23I = \frac{2ML^2}{3}, so the answer is (c).
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