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JEE Main 2022 (26 Jun, Shift 1) · Simple Pendulum

Simple Pendulum question from JEE Main 2022 (26 Jun, Shift 1)

Q54JEE Main 2022 · 26 JUN · SHIFT 1Easy

Simple Pendulum

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with g6\frac{g}{6} vertically upwards then the time period will be:

(Where g = acceleration due to gravity)

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Answer: (c)

  1. Lift accelerating up: geff=g+g6=7g6g_{eff} = g + \frac{g}{6} = \frac{7g}{6}.
  2. T′=Tggeff=67TT' = T\sqrt{\frac{g}{g_{eff}}} = \sqrt{\frac{6}{7}}T
  3. So the answer is (c).
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