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JEE Main 2021 (16 Mar, Shift 1) · Simple Pendulum

Simple Pendulum question from JEE Main 2021 (16 Mar, Shift 1)

Q64JEE Main 2021 · 16 MAR · SHIFT 1Easy

Simple Pendulum

Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g/2, the time period of pendulum will be:

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Answer: (b)

Lift accelerating up: $g_{eff} = g + \frac{g}{2} = \frac{3g}{2}$ .
$T' = T\sqrt{\frac{g}{g_{eff}}} = \sqrt{\frac{2}{3}}T$
So the answer is (b).

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