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JEE Main 2017 (8 Apr, Shift 1) · Applications of Dimensional Analysis

Applications of Dimensional Analysis question from JEE Main 2017 (8 Apr, Shift 1)

Q64JEE Main 2017 · 8 APR · SHIFT 1Easy

Applications of Dimensional Analysis

Time (T), velocity (C) and angular momentum (h) are chosen as fundamentalquantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

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Answer: (a)

  1. Angular momentum h=mvrh = mvr with r=CTr = CT, so h=MC2Th = M C^2 T.
  2. M=h C−2T−1M = h\,C^{-2}T^{-1}.
  3. So the answer is (a) [M]=[T−1C−2h][M] = [T^{-1}C^{-2}h].
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