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JEE Main 2024 (9 Apr, Shift 2) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2024 (9 Apr, Shift 2)

Q7JEE Main 2024 · 9 APR · SHIFT 2Medium

Ohm's Law, Resistivity & Temperature

To determine the resistance (R) of a wire, a circuit is designed below. The $V\text{-}I$ characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of $R$ is _________ $\Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 2500

The voltmeter reads the voltage across $R$ in parallel with $10\text{ k}\Omega$ ; the mA meter reads the total current.
Slope of graph: $R_{eq} = \dfrac{V}{I} = \dfrac{4}{2 \times 10^{-3}} = 2000\ \Omega$
$\dfrac{10000\,R}{R + 10000} = 2000 \Rightarrow 8000R = 2 \times 10^7$
$R = 2500\ \Omega$

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