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NEET 2000 (AIPMT) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from NEET 2000 (AIPMT)

Q42NEET 2000 · AIPMTEasy

Degrees of Freedom & Internal Energy

To find out degree of freedom, the expansion is

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Answer: (a)

  1. Cv=f2RC_v = \frac{f}{2}R, Cp=(f2+1)RC_p = \left(\frac{f}{2} + 1\right)R, so γ=1+2f\gamma = 1 + \frac{2}{f}.
  2. γ−1=2f⇒f=2γ−1\gamma - 1 = \frac{2}{f} \Rightarrow f = \frac{2}{\gamma - 1}
  3. So the answer is (a).
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