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JEE Main 2016 (10 Apr, Shift 1) · Logic Gates

Logic Gates question from JEE Main 2016 (10 Apr, Shift 1)

Q157JEE Main 2016 · 10 APR · SHIFT 1Medium

Logic Gates

To get an output of 1 from the circuit shown in figure the input must be:

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Answer: (c)

$Y = (a + b)\cdot c$ .
Need $c = 1$ and at least one of $a, b = 1$ .
(c) $a = 1, b = 0, c = 1$ : $Y = (1 + 0)\cdot 1 = 1$ . Others give 0.
So the answer is (c).

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