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JEE Main 2019 (10 Jan, Shift 1) · Logic Gates

Logic Gates question from JEE Main 2019 (10 Jan, Shift 1)

Q147JEE Main 2019 · 10 JAN · SHIFT 1Medium

Logic Gates

To get output 1 at R, for the given logic gate circuit the input values must be

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Answer: (b)

OR gate gets $\bar{x}$ and $y$ : $P = \bar{x} + y$ .
NAND gets $x$ and $\bar{y}$ : $Q = \overline{x\bar{y}} = \bar{x} + y$ .
$R = \overline{P + Q} = \overline{\bar{x} + y} = x\bar{y}$ .
$R = 1$ only when $x = 1, y = 0$ . So the answer is (b).

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