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MHT CET 2026 (20 May, Shift 1) · Logic Gates

Logic Gates question from MHT CET 2026 (20 May, Shift 1)

Q9MHT CET 2026 · 20 MAY · SHIFT 1Medium

Logic Gates

To get output zero for the following circuit, the correct choice for the input is

Figure

a. A=1,B=1,C=0A = 1, B = 1, C = 0

b. A=0,B=1,C=0A = 0, B = 1, C = 0

c. A=1,B=1,C=1A = 1, B = 1, C = 1

d. A=1,B=0,C=1A = 1, B = 0, C = 1

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Answer: (a)

  1. Circuit: Y=(A+B)⋅CY = (A + B) \cdot C.
  2. If C=0C = 0, then Y=0Y = 0 whatever AA and BB are.
  3. Choices a (C=0C = 0) and b (C=0C = 0) give Y=0Y = 0; c and d give Y=(1)⋅1=1Y = (1) \cdot 1 = 1.
  4. So the answer is (a) a and b.
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