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MHT CET 2026 (15 Apr, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from MHT CET 2026 (15 Apr, Shift 2)

Q12MHT CET 2026 · 15 APR · SHIFT 2Easy

Stationary Waves & Vibrating Strings

To increase the frequency of transverse oscillations of a stretched string by 40%, the tension must be increased by

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Answer: (c)

  1. f∝T⇒T2T1=(f2f1)2f \propto \sqrt{T} \Rightarrow \dfrac{T_2}{T_1} = \left(\dfrac{f_2}{f_1}\right)^2.
  2. T2T1=(1.4)2=1.96\dfrac{T_2}{T_1} = (1.4)^2 = 1.96.
  3. Increase =96%= 96\%.
  4. So the answer is (c) 96%96\%.
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