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MHT CET 2023 (11 May, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2023 (11 May, Shift 1)

Q60MHT CET 2023 · 11 MAY · SHIFT 1Medium

Self-Inductance & Energy

To manufacture a solenoid of length 1 m1\text{ m} and inductance 1 mH1\text{ mH}, the length of thin wire required is (cross - sectional diameter of a solenoid is considerably less than the length)

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Answer: (b)

  1. Wire length needed: w=4πlLμ0w = \sqrt{\dfrac{4\pi l L}{\mu_0}} (from L=μ0w24πlL = \dfrac{\mu_0 w^2}{4\pi l}).
  2. w=4π×1×10−34π×10−7=104=100w = \sqrt{\dfrac{4\pi \times 1 \times 10^{-3}}{4\pi \times 10^{-7}}} = \sqrt{10^4} = 100 m
  3. So the answer is (b) 0.10 km.
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