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JEE Main 2025 (22 Jan, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2025 (22 Jan, Shift 2)

Q49JEE Main 2025 · 22 JAN · SHIFT 2Medium

Logic Gates

To obtain the given truth table, following logic gate should be placed at G:

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Answer: (a)

The two AND gates give $A\bar{B}$ and $\bar{A}B$ (each gets one input inverted).
Required table: $Y = 1$ for $00$ and $11$ , $Y = 0$ for $01$ and $10$ , which is XNOR.
$\overline{A\bar{B} + \bar{A}B}$ is XNOR, so G must be OR followed by NOT.
So the answer is (a) NOR gate.

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