Logic Gates question from MHT CET 2023 (10 May, Shift 1)

Answer: (d)

1. $Y = A + G(A, B)$. Rows with $A = 1$ give 1 automatically.
2. For $A = 0$ the table needs $G(0,0) = 1$ and $G(0,1) = 0$.
3. NOR: $\overline{0 + 0} = 1$, $\overline{0 + 1} = 0$. NAND gives 1 at $(0,1)$; AND and OR give 0 at $(0,0)$.
4. So the answer is (d) NOR.