To produce an instantaneous displacement current of 2 mA in the space between the parallel plates of a capacitor of capacitance 4, the rate of change of applied variable potential difference (dV/dt) must be:- (a) 800 V/s (b) 500 V/s (c) 200 V/s (d) 400 V/s

Answer: (b). Id = CdV/dt ⇒ dV/dt = Id/C dV/dt = 2×10⁻³4×10⁻⁶ = 500 V/s So the answer is (b) 500 V/s.

To produce an instantaneous displacement current of 2 mA in the space… | NEET 2023

Q18NEET 2023Easy

Capacitors in DC Circuits & RC

To produce an instantaneous displacement current of $2\text{ mA}$ in the space between the parallel plates of a capacitor of capacitance $4\ \mu\text{F}$ , the rate of change of applied variable potential difference $\left(\frac{dV}{dt}\right)$ must be :-

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Answer: (b)

$I_d = C\dfrac{dV}{dt} \Rightarrow \dfrac{dV}{dt} = \dfrac{I_d}{C}$
$\dfrac{dV}{dt} = \dfrac{2\times10^{-3}}{4\times10^{-6}} = 500\text{ V/s}$
So the answer is (b) $500\text{ V/s}$ .

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