To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained: If V0 is almost zero, identify the correct statement: (a) The value of the resistance R is 1.5 Ω (b) The emf of the battery is l.5 V and its internal resistance is 1.5 Ω (c) The emf of the battery is l.5 V and the value of R is 1.5 Ω (d) The potential difference across the battery is 1.5 V when it sends a current of 1000 mA

Answer: (b). Voltmeter across the battery reads V = E - Ir. Intercept at I = 0: E = 1.5 V V ≈ 0 at I = 1 A: r = 1.5/1 = 1.5 Ω So the answer is (b) emf 1.5 V and internal resistance 1.5 Ω.

To verify Ohm's law, a student connects the voltmeter across the… | JEE Main 2019 (12 Apr, Shift 1)

Q33JEE Main 2019 · 12 APR · SHIFT 1Medium

Cells: EMF, Internal Resistance & Combinations

To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained:

If V0 is almost zero, identify the correct statement:

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Answer: (b)

Voltmeter across the battery reads $V = E - Ir$ .
Intercept at $I = 0$ : $E = 1.5\text{ V}$
$V \approx 0$ at $I = 1\text{ A}$ : $r = \frac{1.5}{1} = 1.5\ \Omega$
So the answer is (b) emf 1.5 V and internal resistance $1.5\ \Omega$ .

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