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MHT CET 2026 (16 Apr, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2026 (16 Apr, Shift 1)

Q4MHT CET 2026 · 16 APR · SHIFT 1Easy

Current Loop as a Magnetic Dipole

Torque acting on a coil carrying current 'I' situated parallel to magnetic field of induction 'B' having of turns 'n' and area 'A' is

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Answer: (b)

  1. Torque on a coil is a vector product: τ⃗=m⃗×B⃗=nI(A⃗×B⃗)\vec\tau = \vec m \times \vec B = nI(\vec A \times \vec B).
  2. With the coil plane parallel to B, A⃗⊥B⃗\vec A \perp \vec B, so τ=nIAB\tau = nIAB (maximum).
  3. So the answer is (b) nI(A⃗×B⃗)nI(\vec A \times \vec B).
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