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JEE Main 2026 (4 Apr, Shift 1) · Logic Gates

Logic Gates question from JEE Main 2026 (4 Apr, Shift 1)

Q33JEE Main 2026 · 4 APR · SHIFT 1Difficult

Logic Gates

Two 4 bits binary numbers, $A = 1101$ and $B = 1010$ are given in the inputs of a logic circuit shown in figure below. The output $(Y)$ will be:

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Answer: (a)

$Y = \overline{\bar{A} \cdot B} = A + \bar{B}$ , applied bit by bit.
$B = 1010 \Rightarrow \bar{B} = 0101$ .
$A + \bar{B} = 1101 + 0101$ (bitwise OR) $= 1101$ .
So the answer is (a) $Y = 1101$ .

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