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JEE Main 2025 (8 Apr, Shift 2) · Comparing Two Projectiles

Comparing Two Projectiles question from JEE Main 2025 (8 Apr, Shift 2)

Q9JEE Main 2025 · 8 APR · SHIFT 2Medium

Comparing Two Projectiles

Two balls with same mass and initial velocity, are projected at different angles in such a way that maximum height reached by first ball is 8 times higher than that of the second ball. T1T_1 and T2T_2 are the total flying times of first and second ball, respectively, then the ratio of T1T_1 and T2T_2 is

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Answer: (c)

  1. Same speed: H∝sin⁡2θH \propto \sin^2\theta and T∝sin⁡θT \propto \sin\theta, so T∝HT \propto \sqrt{H}.
  2. T1T2=H1H2=8=22\frac{T_1}{T_2} = \sqrt{\frac{H_1}{H_2}} = \sqrt{8} = 2\sqrt{2}
  3. So the answer is (c) 22:12\sqrt{2} : 1.
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