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NEET 2002 (AIPMT) · Vibration Magnetometer

Vibration Magnetometer question from NEET 2002 (AIPMT)

Q19NEET 2002 · AIPMTEasy

Vibration Magnetometer

Two bar magnets having same geometry with magnetic moments M and 2M, are firstly placed in such a way that their similar poles are same side then its time period of oscillation is T1. Now the polarity of one of the magnet is reversed then time period of oscillation is T2, then

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Answer: (a)

  1. Like poles together (sum position): moment 3M3M, inertia 2I2I: T1=2π2I3MBT_1 = 2\pi\sqrt{\frac{2I}{3MB}}
  2. One reversed (difference position): moment MM: T2=2π2IMBT_2 = 2\pi\sqrt{\frac{2I}{MB}}
  3. T1T2=13<1\frac{T_1}{T_2} = \frac{1}{\sqrt{3}} < 1
  4. So the answer is (a) T1<T2T_1 < T_2.
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