Two bar magnets ' P ' and ' Q ' are kept in uniform magnetic field '… | MHT CET 2021 (24 Sep, Shift 2)

Q11MHT CET 2021 · 24 SEP · SHIFT 2Medium

Vibration Magnetometer

Two bar magnets ' $\mathrm{P}$ ' and ' $\mathrm{Q}$ ' are kept in uniform magnetic field ' $\mathrm{B}$ ' with magnetic moments ' $\mathrm{M}_{\mathrm{P}}$ ' and ' $\mathrm{M}_{\mathrm{Q}}$ ' respectively. Magnet 'P' is oscillating with frequency twice that of magnet 'Q'. If the moment of inertia of the magnet 'P' is twice that of magnet 'Q' then

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Answer: (c)

$f = \frac{1}{2\pi}\sqrt{\frac{MB}{I}} \Rightarrow M \propto f^2 I$ (same $B$ )
$\frac{M_P}{M_Q} = \left(\frac{f_P}{f_Q}\right)^2\frac{I_P}{I_Q} = 4 \times 2 = 8$
So the answer is (c) $M_P = 8M_Q$ .

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Vibration Magnetometer question from MHT CET 2021 (24 Sep, Shift 2)

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