Two batteries, one of emf 18 volts and internal resistance 2 Ω and the other of emf 12 volts and internal resistance 1 Ω, are connected as shown. The voltmeter V will record a reading of (a) 30 volt (b) 18 volt (c) 15 volt (d) 14 volt

Answer: (d). From the figure both batteries are connected in parallel with like terminals together. V = (E₁/r₁ + E₂/r₂)/(1/r₁ + 1/r₂) = (18/2 + 12/1)/(1/2 + 1) = 21/1.5 V = 14 V. So the answer is (d) 14 volt.

Two batteries, one of emf 18 volts and internal resistance 2 Ω and… | NEET 2005 (AIPMT)

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Cells: EMF, Internal Resistance & Combinations

Two batteries, one of emf 18 volts and internal resistance 2 $\Omega$ and the other of emf 12 volts and internal resistance 1 $\Omega$ , are connected as shown. The voltmeter V will record a reading of

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Answer: (d)

From the figure both batteries are connected in parallel with like terminals together.
$V = \frac{E_1/r_1 + E_2/r_2}{1/r_1 + 1/r_2} = \frac{18/2 + 12/1}{1/2 + 1} = \frac{21}{1.5}$
$V = 14\text{ V}$ . So the answer is (d) 14 volt.

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