Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 Ω. The internal resistances of the two batteries are 1 Ω and 2 Ω respectively. The voltage across the load lies between: (a) 11.7 V and 11.8 V (b) 11.6 V and 11.7 V (c) 11.5 V and 11.6 V (d) 11.4 V and 11.5 V

Answer: (c). Cells in parallel with a load (Millman): V = (E₁/r₁ + E₂/r₂)/(1/r₁ + 1/r₂ + 1/R). V = (12/1 + 13/2)/(1 + 0.5 + 0.1) = (18.5)/(1.6) V = 11.56 V So the answer is (c) between 11.5 V and 11.6 V.

Two batteries with e.m.f 12 V and 13 V are connected in parallel… | JEE Main 2018

Q37JEE Main 2018Medium

Cells: EMF, Internal Resistance & Combinations

Two batteries with e.m.f 12 V and 13 V are connected in parallel across a load resistor of 10 $\Omega$ . The internal resistances of the two batteries are 1 $\Omega$ and 2 $\Omega$ respectively. The voltage across the load lies between:

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Answer: (c)

Cells in parallel with a load (Millman): $V = \dfrac{E_1/r_1 + E_2/r_2}{1/r_1 + 1/r_2 + 1/R}$ .
$V = \dfrac{12/1 + 13/2}{1 + 0.5 + 0.1} = \dfrac{18.5}{1.6}$
$V = 11.56\text{ V}$
So the answer is (c) between 11.5 V and 11.6 V.

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