Physics Circle home Student Login

Home›Chapters›Laws of Motion PYQs›Connected Bodies & Pulleys›Question 38

JEE Main 2013 (22 Apr, Shift 1) · Connected Bodies & Pulleys

Connected Bodies & Pulleys question from JEE Main 2013 (22 Apr, Shift 1)

Q38JEE Main 2013 · 22 APR · SHIFT 1Medium

Connected Bodies & Pulleys

Two blocks of mass M1=20M_1 = 20 kg and M2=12M_2 = 12 kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is:

Figure

Show answer and solution

Answer: (d)

  1. Total mass =20+8+12=40 kg= 20 + 8 + 12 = 40\text{ kg}: a=480−40040=2 m/s2a = \dfrac{480 - 400}{40} = 2\text{ m/s}^2 upward.
  2. Below the mid-point hang M2M_2 and half the rod: 12+4=16 kg12 + 4 = 16\text{ kg}.
  3. T=16(g+a)=16×12=192 NT = 16(g + a) = 16 \times 12 = 192\text{ N}
  4. So the answer is (d) 192 N.
Report a mistake

More questions on Connected Bodies & Pulleys