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MHT CET 2024 (10 May, Shift 2) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2024 (10 May, Shift 2)

Q21MHT CET 2024 · 10 MAY · SHIFT 2Medium

Rotational Kinetic Energy, Work & Power

Two bodies A and B have their moments of inertia I1I_1 and I2I_2 respectively about their axis of rotation. If their kinetic energies of rotation are equal and their angular momenta L1L_1 and L2L_2 respectively are in the ratio 1:31 : \sqrt{3}, then I2I_2 will be

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Answer: (d)

  1. Equal KK: L=2IK⇒L1L2=I1I2L = \sqrt{2IK} \Rightarrow \frac{L_1}{L_2} = \sqrt{\frac{I_1}{I_2}}
  2. 13=I1I2⇒I1I2=13\frac{1}{\sqrt{3}} = \sqrt{\frac{I_1}{I_2}} \Rightarrow \frac{I_1}{I_2} = \frac{1}{3}
  3. So the answer is (d) 3I13I_1.
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