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MHT CET 2025 (20 Apr, Shift 2) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2025 (20 Apr, Shift 2)

Q3MHT CET 2025 · 20 APR · SHIFT 2Medium

Equations of Kinematics

Two bodies A and B move in same straight line starting from same position. Body A moves with constant velocity ' u ' and body B moves with constant acceleration ' aa '. When their velocities become equal, the distance between them is

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Answer: (d)

  1. Velocities are equal when at=u⇒t=uaat = u \Rightarrow t = \frac{u}{a}.
  2. sA=ut=u2as_A = ut = \frac{u^2}{a}, sB=12at2=u22as_B = \frac{1}{2}at^2 = \frac{u^2}{2a}
  3. Gap =u2a−u22a=u22a= \frac{u^2}{a} - \frac{u^2}{2a} = \frac{u^2}{2a}
  4. So the answer is (d) u22a\frac{u^2}{2a}.
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