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JEE Main 2025 (29 Jan, Shift 2) · Spring Systems

Spring Systems question from JEE Main 2025 (29 Jan, Shift 2)

Q25JEE Main 2025 · 29 JAN · SHIFT 2Easy

Spring Systems

Two bodies A and B of equal mass are suspended from two massless springs of spring constant k1 and k2, respectively. If the bodies oscillate vertically such that their amplitudes are equal, the ratio of the maximum velocity of A to the maximum velocity of B is

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Answer: (b)

$v_{max} = A\sqrt{\frac{k}{m}}$ ; with equal $A$ and $m$ , $v_{max} \propto \sqrt{k}$ .
$\frac{v_A}{v_B} = \sqrt{\frac{k_1}{k_2}}$
So the answer is (b) $\sqrt{\frac{k_1}{k_2}}$ .

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