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MHT CET 2020 (19 Oct, Shift 2) · Spring Systems

Spring Systems question from MHT CET 2020 (19 Oct, Shift 2)

Q79MHT CET 2020 · 19 OCT · SHIFT 2Easy

Spring Systems

Two bodies $A$ and $B$ of equal mass are suspended from two separate massles springs of force constant $k_1$ and $k_2$ , respectively. The bodies oscillate vertically such that their maximum velocities are equal. The ratio of the amplitudes of body $A$ to that of body $B$ is

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Answer: (a)

$v_{max} = A\sqrt{\frac{k}{m}}$ ; equal $v_{max}$ and $m$ give $A \propto \frac{1}{\sqrt{k}}$ .
$\frac{A_A}{A_B} = \sqrt{\frac{k_2}{k_1}}$
So the answer is (a) $\sqrt{\frac{k_2}{k_1}}$ .

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