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MHT CET 2024 (4 May, Shift 1) · Spring Systems

Spring Systems question from MHT CET 2024 (4 May, Shift 1)

Q39MHT CET 2024 · 4 MAY · SHIFT 1Easy

Spring Systems

Two bodies A and B of equal mass are suspended from two separate massless springs of spring constants $K_1$ and $K_2$ respectively. The two bodies oscillate vertically such that their maximum velocities are equal. The ratio of the amplitude of $B$ to that of $A$ is

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Answer: (c)

$v_{max} = A\sqrt{\frac{K}{m}}$ ; equal $v_{max}$ and $m$ give $A \propto \frac{1}{\sqrt{K}}$ .
$\frac{A_B}{A_A} = \sqrt{\frac{K_1}{K_2}}$ (A has $K_1$ , B has $K_2$ ).
So the answer is (c) $\sqrt{\frac{K_1}{K_2}}$ .

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