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MHT CET 2021 (20 Sep, Shift 1) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2021 (20 Sep, Shift 1)

Q25MHT CET 2021 · 20 SEP · SHIFT 1Easy

Equations of Kinematics

Two bodies 'AA' and 'BB' start from the same point at the same instant and move along a straight line. 'A' moves with uniform acceleration (a) and 'B' moves with uniform velocity (V). They meet after time 't'. The value of 't' is

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Answer: (a)

  1. They meet when both displacements are equal: sA=12at2s_A = \frac{1}{2}at^2, sB=Vts_B = Vt.
  2. 12at2=Vt⇒t=2Va\frac{1}{2}at^2 = Vt \Rightarrow t = \frac{2V}{a}
  3. So the answer is (a) 2Va\frac{2V}{a}.
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