Physics Circle home Student Login

Home›Chapters›Motion in One Dimension PYQs›Equations of Kinematics›Question 16

MHT CET 2023 (13 May, Shift 2) · Equations of Kinematics

Equations of Kinematics question from MHT CET 2023 (13 May, Shift 2)

Q16MHT CET 2023 · 13 MAY · SHIFT 2Easy

Equations of Kinematics

Two bodies AA and BB start from the same point at the same instant and move along a straight line. Body AA moves with uniform acceleration aa and body BB moves with uniform velocity vv. They meet after time tt. The value of tt is

Show answer and solution

Answer: (a)

  1. They meet when both displacements are equal: sA=12at2s_A = \frac{1}{2}at^2, sB=vts_B = vt.
  2. 12at2=vt⇒t=2va\frac{1}{2}at^2 = vt \Rightarrow t = \frac{2v}{a}
  3. So the answer is (a) 2va\frac{2v}{a}.
Report a mistake

More questions on Equations of Kinematics