Physics Circle home Student Login

Home›Chapters›Circular Motion PYQs›Centripetal Acceleration & Force›Question 3

MHT CET 2025 (23 Apr, Shift 1) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2025 (23 Apr, Shift 1)

Q3MHT CET 2025 · 23 APR · SHIFT 1Easy

Centripetal Acceleration & Force

Two bodies of mass 10 kg and 5 kg are moving in concentric circular orbits of radii ' R ' and ' r ' respectively such that their periods are same. The ratio between their centripetal acceleration is

Show answer and solution

Answer: (a)

  1. Same period ⇒\Rightarrow same ω\omega. Centripetal acceleration a=ω2ra = \omega^2 r.
  2. a1:a2=R:ra_1 : a_2 = R : r (mass does not matter).
  3. So the answer is (a) R/rR/r.
Report a mistake

More questions on Centripetal Acceleration & Force