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MHT CET 2022 (11 Aug, Shift 2) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2022 (11 Aug, Shift 2)

Q28MHT CET 2022 · 11 AUG · SHIFT 2Medium

Centripetal Acceleration & Force

Two bodies of masses ' $m$ ' and ' $3m$ ' are rotating in horizontal circles of radii ' $r$ ' and ' $\frac{r}{3}$ ' respectively. The tangential speed of the body of mass ' $m$ ' is $n$ times that of the heavier body; while the centripetal force is same for both. The value of $n$ is

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Answer: (a)

Equal forces: $\frac{m v_1^2}{r} = \frac{3m v_2^2}{r/3} = \frac{9 m v_2^2}{r}$ .
$v_1^2 = 9 v_2^2 \Rightarrow v_1 = 3 v_2$
So $n = 3$ . The answer is (a) 3.

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