Two bodies rotate with kinetic energies 'E 1 ' and 'E 2 '. Moments of inertia about their axis of rotation are 'I 1 ' and 'I 2 '. If I₁ = I₂/3 and E 1 = 27 E 2, then the ratio of angular momenta 'L 1 ' to 'L 2 ' is (a) 1: 3 (b) 3: 1 (c) 1: 1 (d) 2: 1

Answer: (b). L = √(2IE) (L₁)/(L₂) = √((I₁ E₁)/(I₂ E₂)) = √(1/3 × 27) = 3 So the answer is (b) 3: 1.

Two bodies rotate with kinetic energies 'E 1 ' and 'E 2 '. Moments of… | MHT CET 2021 (20 Sep, Shift 1)

Q38MHT CET 2021 · 20 SEP · SHIFT 1Medium

Rotational Kinetic Energy, Work & Power

Two bodies rotate with kinetic energies 'E $1$ ' and 'E $2$ '. Moments of inertia about their axis of rotation are 'I $1$ ' and 'I $2$ '. If $I_1 = \frac{I_2}{3}$ and E $1$ = 27 E $2$ , then the ratio of angular momenta 'L $1$ ' to 'L $2$ ' is

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Answer: (b)

$L = \sqrt{2IE}$
$\frac{L_1}{L_2} = \sqrt{\frac{I_1 E_1}{I_2 E_2}} = \sqrt{\frac{1}{3} \times 27} = 3$
So the answer is (b) 3: 1.

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