Two bodies rotate with kinetic energies E₁ and E₂, moment of inertia about their axes of rotation is I₁ and I₂. If 3I₁ = I₂ and E₁ = 27E₂ then the ratio of the angular momenta L₁ to L₂ is (a) 9: 1 (b) 3: 1 (c) 27: 1 (d) 1: 1

Answer: (b). L = √(2IE) (L₁)/(L₂) = √((I₁ E₁)/(I₂ E₂)) = √(1/3 × 27) = √(9) = 3 So the answer is (b) 3: 1.

Two bodies rotate with kinetic energies E₁ and E₂, moment of inertia… | MHT CET 2026 (12 May, Shift 2)

Q5MHT CET 2026 · 12 MAY · SHIFT 2Medium

Rotational Kinetic Energy, Work & Power

Two bodies rotate with kinetic energies $E_1$ and $E_2$ , moment of inertia about their axes of rotation is $I_1$ and $I_2$ . If $3I_1 = I_2$ and $E_1 = 27E_2$ then the ratio of the angular momenta $L_1$ to $L_2$ is

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Answer: (b)

$L = \sqrt{2IE}$
$\frac{L_1}{L_2} = \sqrt{\frac{I_1 E_1}{I_2 E_2}} = \sqrt{\frac{1}{3} \times 27} = \sqrt{9} = 3$
So the answer is (b) $3 : 1$ .

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