Two bodies 'X' and 'Y' at temperatures T₁ K and T₂ K respectively have the same dimensions. Their emissivities e₁ and e₂ are in the ratio of 1: 6. If their emissive powers are same, the relation between their temperatures is (a) T₁: T₂ = 41/4: 1 (b) T₁: T₂ = 51/4: 1 (c) T₁: T₂ = 61/4: 1 (d) T₁: T₂ = 71/4: 1

Answer: (c). Emissive power E = eσ T⁴; equal E gives e₁ T₁⁴ = e₂ T₂⁴. ((T₁)/(T₂))⁴ = (e₂)/(e₁) = 6 (T₁)/(T₂) = 61/4 So the answer is (c) 61/4: 1.

Two bodies 'X' and 'Y' at temperatures T₁ K and T₂ K respectively… | MHT CET 2026 (20 May, Shift 1)

Q14MHT CET 2026 · 20 MAY · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

Two bodies 'X' and 'Y' at temperatures $T_1$ K and $T_2$ K respectively have the same dimensions. Their emissivities $e_1$ and $e_2$ are in the ratio of $1 : 6$ . If their emissive powers are same, the relation between their temperatures is

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Answer: (c)

Emissive power $E = e\sigma T^4$ ; equal $E$ gives $e_1 T_1^4 = e_2 T_2^4$ .
$\left(\dfrac{T_1}{T_2}\right)^4 = \dfrac{e_2}{e_1} = 6$
$\dfrac{T_1}{T_2} = 6^{1/4}$
So the answer is (c) $6^{1/4} : 1$ .

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Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (20 May, Shift 1)

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