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NEET 2005 (AIPMT) · Relative Velocity in Two Dimensions

Relative Velocity in Two Dimensions question from NEET 2005 (AIPMT)

Q25NEET 2005 · AIPMTMedium

Relative Velocity in Two Dimensions

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

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Answer: (d)

  1. Meeting point C: BC=v1tBC = v_1 t, AC=vtAC = vt, right angle at B.
  2. (vt)2=a2+(v1t)2(vt)^2 = a^2 + (v_1 t)^2
  3. t=a2v2−v12t = \sqrt{\frac{a^2}{v^2 - v_1^2}}
  4. So the answer is (d).
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