Two capacitors C₁ = 3 and C₂ = 2 are connected in series across d.c. source of 100 V. The ratio of the potential across C₂ to C₁ is (a) 2: 3 (b) 3: 2 (c) 6: 5 (d) 5: 6

Answer: (b). Series: same charge, so V ∝ 1/C. (V₂)/(V₁) = (C₁)/(C₂) = 3/2 So the answer is (b) 3: 2.

Two capacitors C₁ = 3 and C₂ = 2 are connected in series across d.c… | MHT CET 2023 (10 May, Shift 1)

Q39MHT CET 2023 · 10 MAY · SHIFT 1Easy

Combination of Capacitors

Two capacitors $C_1 = 3\ \mu\text{F}$ and $C_2 = 2\ \mu\text{F}$ are connected in series across d.c. source of $100\text{ V}$ . The ratio of the potential across $C_2$ to $C_1$ is

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Answer: (b)

Series: same charge, so $V \propto \frac{1}{C}$ .
$\frac{V_2}{V_1} = \frac{C_1}{C_2} = \frac{3}{2}$
So the answer is (b) $3 : 2$ .

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