Two capacitors of 100 and 50 are connected in parallel. If the potential difference across 100 is 20 V and across 50 is 40 V, then the common potential of the parallel combination will be (same polarities of the capacitor connected together) (a) 20 V (b) 60 V (c) 3/80 (d) 80/3 V

Answer: (d). V = (C₁V₁ + C₂V₂)/(C₁ + C₂) V = (100 × 20 + 50 × 40)/(150) = (4000)/(150) = 80/3 V So the answer is (d) 80/3 V.

Two capacitors of 100 and 50 are connected in parallel. If the… | MHT CET 2025 (23 Apr, Shift 2)

Q7MHT CET 2025 · 23 APR · SHIFT 2Easy

Charge Sharing & Loss of Energy

Two capacitors of $100\ \mu\text{F}$ and $50\ \mu\text{F}$ are connected in parallel. If the potential difference across $100\ \mu\text{F}$ is 20 V and across $50\ \mu\text{F}$ is 40 V, then the common potential of the parallel combination will be (same polarities of the capacitor connected together)

Show answer and solution

Answer: (d)

$V = \frac{C_1V_1 + C_2V_2}{C_1 + C_2}$
$V = \frac{100 \times 20 + 50 \times 40}{150} = \frac{4000}{150} = \frac{80}{3}\ \text{V}$
So the answer is (d) $\frac{80}{3}$ V.

Report a mistake

Charge Sharing & Loss of Energy question from MHT CET 2025 (23 Apr, Shift 2)

More questions on Charge Sharing & Loss of Energy