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JEE Main 2020 (5 Sep, Shift 1) · Charge Sharing & Loss of Energy

Charge Sharing & Loss of Energy question from JEE Main 2020 (5 Sep, Shift 1)

Q29JEE Main 2020 · 5 SEP · SHIFT 1Medium

Charge Sharing & Loss of Energy

Two capacitors of capacitances C and 2C are charged to potential differences V and 2V, respectively. These are then connected in parallel in such a manner that the positive terminal of one is connected to the negative terminal of the other. The final energy of this configuration is:

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Answer: (b)

  1. Charges CVCV and 2C×2V=4CV2C \times 2V = 4CV; opposite plates joined, net charge =3CV= 3CV.
  2. Common potential V′=3CVC+2C=VV' = \frac{3CV}{C + 2C} = V
  3. U=12(3C)V2=32CV2U = \frac{1}{2}(3C)V^2 = \frac{3}{2}CV^2
  4. So the answer is (b).
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