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MHT CET 2020 (19 Oct, Shift 2) · Combination of Capacitors

Combination of Capacitors question from MHT CET 2020 (19 Oct, Shift 2)

Q70MHT CET 2020 · 19 OCT · SHIFT 2Medium

Combination of Capacitors

Two capacitors of capacities 2 μF2\ \mu\text{F} and 4 μF4\ \mu\text{F} are connected in parallel. A third capacitor of 6 μF6\ \mu\text{F} capacity is connected in series with this combination. A battery of 12 V is connected across this combination. The charge on 2 μF2\ \mu\text{F} capacitor is

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Answer: (a)

  1. 2+4=6 μF2 + 4 = 6\ \mu\text{F} in parallel, in series with 6 μF6\ \mu\text{F}: Ceq=3 μFC_{eq} = 3\ \mu\text{F}.
  2. Total charge Q=3×12=36 μCQ = 3\times12 = 36\ \mu\text{C}.
  3. Voltage across parallel part =366=6 V= \frac{36}{6} = 6\ \text{V}.
  4. Charge on 2 μF2\ \mu\text{F} =2×6=12 μC= 2\times6 = 12\ \mu\text{C}. So the answer is (a).
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