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MHT CET 2024 (15 May, Shift 1) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2024 (15 May, Shift 1)

Q30MHT CET 2024 · 15 MAY · SHIFT 1Easy

Angle of Contact & Capillarity

Two capillary tubes A and B of the same internal diameter are kept vertically in two different liquids whose densities are in the ratio 4:34 : 3. If the surface tensions of these two liquids are in the ratio 6:56 : 5, then the ratio of rise of liquid in capillary A to that in B is (assume their angles of contact are nearly equal)

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Answer: (b)

  1. h=2Tcos⁡θrρg∝Tρh = \frac{2T\cos\theta}{r\rho g} \propto \frac{T}{\rho} (same rr, θ\theta).
  2. hAhB=65×34=910\frac{h_A}{h_B} = \frac{6}{5} \times \frac{3}{4} = \frac{9}{10}
  3. So the answer is (b) 9:109 : 10.
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