Two capillary tubes of different diameters are dipped in water. The rise of water is (a) zero in both the tubes. (b) same in both the tubes. (c) more in the tube of larger diameter. (d) more in the tube of smaller diameter.

Answer: (d). h = (2Tcos θ)/(rρ g), so h ∝ 1/r for the same liquid. The narrower tube has the larger rise. So the answer is (d) more in the tube of smaller diameter.

Two capillary tubes of different diameters are dipped in water. The… | MHT CET 2019 (2 May, Shift 1)

Q60MHT CET 2019 · 2 MAY · SHIFT 1Easy

Angle of Contact & Capillarity

Two capillary tubes of different diameters are dipped in water. The rise of water is

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Answer: (d)

$h = \frac{2T\cos\theta}{r\rho g}$ , so $h \propto \frac{1}{r}$ for the same liquid.
The narrower tube has the larger rise.
So the answer is (d) more in the tube of smaller diameter.

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