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MHT CET 2025 (21 Apr, Shift 2) · Angle of Contact & Capillarity

Angle of Contact & Capillarity question from MHT CET 2025 (21 Apr, Shift 2)

Q17MHT CET 2025 · 21 APR · SHIFT 2Easy

Angle of Contact & Capillarity

Two capillary tubes of same diameter are kept vertically in two liquids whose densities are in the ratio 4:34 : 3. If their surface tensions are in the ratio 6:56 : 5, the ratio of heights (h1h2)\left(\frac{h_1}{h_2}\right) of liquids in the two capillary tubes is (Their angle of contacts are same)

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Answer: (b)

  1. h=2Tcos⁡θrρg∝Tρh = \frac{2T\cos\theta}{r\rho g} \propto \frac{T}{\rho} (same rr, θ\theta).
  2. h1h2=T1T2⋅ρ2ρ1=65×34=910\frac{h_1}{h_2} = \frac{T_1}{T_2} \cdot \frac{\rho_2}{\rho_1} = \frac{6}{5} \times \frac{3}{4} = \frac{9}{10}
  3. So the answer is (b) 910\frac{9}{10}.
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