Two Carnot engines A and B are operated in series. The first one, A… | JEE Main 2019 (9 Jan, Shift 2)

Q59JEE Main 2019 · 9 JAN · SHIFT 2Medium

Heat Engines, Refrigerators & Second Law

Two Carnot engines A and B are operated in series. The first one, A, receives heat at T1 (= 600 K) and rejects to a reservoir at temperature T2. The second engine B receives heat rejected by the first engine and, in turn, rejects to a heat reservoir at T3 (=400 K). Calculate the temperature T2 if the work outputs of the two engines are equal:

Show answer and solution

Answer: (d)

For Carnot engines $Q \propto T$ : $W_A = k(T_1 - T_2)$ , $W_B = k(T_2 - T_3)$ .
$W_A = W_B \Rightarrow T_2 = \frac{T_1 + T_3}{2} = \frac{600 + 400}{2}$
$T_2 = 500\text{ K}$ . So the answer is (d) 500 K.

Report a mistake

More questions on Heat Engines, Refrigerators & Second Law

Three Carnot engines operate in series between a heat source at a temperature T1 and a…JEE Main 2019 (10 Jan, Shift 1)
The efficiency of an ideal heat engine working between the freezing point and boiling…NEET 2018
Two Carnot engines A and B are operated in series. Engine A receives heat from a…JEE Main 2018 (15 Apr, Shift 2)
A Carnot's engine works as a refrigerator between 250 K and 300 K. It receives 500 cal…JEE Main 2018 (15 Apr, Shift 1)
A carnot engine having an efficiency of 1/10 as heat engine, is used as a refrigerator…NEET 2017
An engine operates by taking n moles of an ideal gas through the cycle ABCDA shown in…JEE Main 2017 (8 Apr, Shift 1)
The temperature inside a refrigerator is t2 oC and the room temperature is t1 oC. The…NEET 2016 (Phase 2)
A refrigerator works between 4oC and 30oC. It is required to remove 600 calories of heat…NEET 2016 (Phase 1)

Heat Engines, Refrigerators & Second Law question from JEE Main 2019 (9 Jan, Shift 2)

More questions on Heat Engines, Refrigerators & Second Law