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NEET 2013 · Heat Engines, Refrigerators & Second Law

Heat Engines, Refrigerators & Second Law question from NEET 2013

Q73NEET 2013Medium

Heat Engines, Refrigerators & Second Law

Two Carnot engines A and B are operated in series. The engine A receives heat from the source at temperature T1 and rejects the heat to the sink at temperature T. The second engine B receives the heat at temperature T and rejects to its sink at temperature T2. For what values of T the efficiencies of the two engines are equal

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Answer: (c)

  1. ηA=1−TT1\eta_A = 1 - \frac{T}{T_1}, ηB=1−T2T\eta_B = 1 - \frac{T_2}{T}.
  2. Equal efficiencies: TT1=T2T⇒T2=T1T2\frac{T}{T_1} = \frac{T_2}{T} \Rightarrow T^2 = T_1T_2.
  3. So the answer is (c) T1T2\sqrt{T_1T_2}.
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