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JEE Main 2024 (9 Apr, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2024 (9 Apr, Shift 2)

Q7JEE Main 2024 · 9 APR · SHIFT 2Easy

Equations of Kinematics

Two cars are travelling towards each other at speed of $20\text{ m s}^{-1}$ each. When the cars are $300\text{ m}$ apart, both the drivers apply brakes and the cars retard at the rate of $2\text{ m s}^{-2}$ . The distance between them when they come to rest is:

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Answer: (b)

Stopping distance of each car: $s = \frac{u^2}{2a} = \frac{20^2}{2 \times 2} = 100\text{ m}$ .
Both cars together cover $2 \times 100 = 200\text{ m}$ .
Gap left $= 300 - 200 = 100\text{ m}$ .
So the answer is (b) 100 m.

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